Question

(c) Aristotle
100
19. How many atoms are present in 49g of H2SO4?
(b) 5 x 6.02 x 1023
(a) 7 x 6.02 x 1023
(c) 6 x 6.02 x 1923
D)7x3.02^23

Answer 1

Answer:

Correct option is

D

7×3.02×10

23

Weight of H

2

SO

4

=w=49g

Molar mass of H

2

SO

4

=M=98g/mol

∴ number of moles of H

2

SO

4

=n=

M

w

=

98

49

=0.5

There are 7 atoms in the H

2

SO

4

∴ total number of atoms =7×n×6.022×10

23

=7×0.5×6.022×10

23

=7×3.02×10

23

Hence, the correct option is (D).

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Answer 2

Answer:

Correct option is

D

7×3.02×1023

Weight of H2SO4=w=49g

Molar mass of H2SO4=M=98g/mol

∴ number of moles of H2SO4=n=Mw=9849=0.5

There are 7 atoms in the H2SO4

∴ total number of atoms =7×n×6.022×1023=7×0.5×6.022×1023=7×3.02×1023

Hence, the correct option is (D).

Explanation:

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