Question

c) Base = 12 cm, altitude = 16 cm Find he 1: hocled tri​

Answer 1

Answer:

R.E.F image

OA=16cm,AB=l

l=

16

2

+12

2

=

256+144

l=20cm

curved surface Area,

C.S.A=πrl=3.14×12×20=753.6cm

2

Total surface Area,

T.S.A=πr(r+l)=3.14×12[12+20]=1205.76cm

2