Question

C]
By which numbers 3, 4, 5, 6, 7, is 250 exactly divisible​

Answer 1

Answer:

prime factors of 2,3,4,5,6 are

2=2*1

3=3*1

4=2^2

5=5*1

6=2*3

Thus LCM(2,3,4,5,6)=2^2*3*5=60

The remainder in all cases is 1

thus the minimum possible No=60+1=61

But 61 is not divisible by 7

Now the numbers with remainder 1 when divided by 2,3,4,5 and 6 are:

61,61+60,+61+2*60,61+3*60,61+4*60,,……………..

61,121,181,241,301…

we have to find the number which is divisible by 7

we observe that 301 is divisible by 7

so the desired number is =301

Now as per required conditions

301 lies between 250 and 350 also

Thus sum of digits of 301

=3+0+1=4

Step-by-step explanation:

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