Question

c) Calculate the number of molecules present in 124 grams of Phosphorus, P
(atomic mass of P-31)
OR​

Answer 1

Answer:Molecular mass of P4 = 124 g/mol. i.e. 31 g P4 = 0.25 x 1023 x 31 = 1.5 x1023 molecules.

Explanation:

Answer 2

Answer:

mass of P = 31

therefore 1 mole of P = 31g which contains =

6.022×10²³ molecules

therefore, given mole = 124g = 4moles

hence no. of molecules = 4×6.022×10²³

= 24.088×10²³

= 2.4088×10²⁴ molecules

hope it helped :)