Question

c) Calculate the wave number and wavelength of a ph
oton when the
electron jumps from n2 =4 to ni = 1
​

Answer 1

The energy of n

th

level for any atom is determined by the radius and quantum number by:

E

n

=−

2ℏ

2

n

2

Z

2

k

e

2

e

4

m

e

For hydrogen atom the energy varies with shell number as:

E

n

=−13.6

n

2

1

eVEnergy energy released from jump of electron from n=∞ to n=1 is:

E=−13.6(

∞

1

−(

1

2

1

))eV

=13.6eVPhoton of this energy is given by, E=

λ

hc

⟹λ=

E

hc

=91.17nm