Math, asked by Raiyankhan6221, 1 month ago

C can complete the work alone in 60 days. A and B take 40% and 75% more time than C. The work was started by A and B, and C worked with A on every third day, In how many day the work will be completed.

Answers

Answered by anchitaagarwal
5

Answer:

48 ⅘

Step-by-step explanation:

C an complete work in = 60 days

A takes 40% more time than C, So time taken by A = (40/100)*60 + 60

                                                                                         = 84 days

B takes 75% more time than C, So time taken by B = 75% of 60 + 60

                                                                                         = (75/100) * 60 + 60

                                                                                         = 105 days

(Note: To make calculation easy take total work as LCM of time taken by A, B and C)

So,

Person   Days     Rate     Total work

A              84         20        1680

B              105        16        1680

C              60          28       1680

For 3 days:

First day A worked alone + second day A worked alone + third day all 3 worked

20 + 20 +(20+16+28)

= 104 unit of work in 3 days

No of days = Total work / Unit in 3 days

                  =  1680 / 104 unit/3days (in integers)

                  =  16 *3 (as rate is per 3 days)

                   = 48 days

now

in 48 days work done = 1664

Remaining work = 1680 -1664 = 16 unit

On 49 day A will work Alone

So,

20 unit work in 1 day

16 unit work in = (1/20)*16

                        = 16/20

                         = 4/5

So total time is 48 ⅘

                 

Answered by amitnrw
0

Given:  C can complete the work alone in 60 days.

A and B take 40% and 75% more time than C.

The work was started by A and B, and C worked with A on every third day, In how many day the work will be completed.

To Find :

Solution:

C can complete the work alone in 60 days.

A can complete work in 60 + (40/100)60  = 84 days

B can complete work in 60 + (75/100)60  = 105 days

Work Done in 3 Days  =

3 * (1/84)  +  1/105  + 1/60

= (15 + 4 + 7)/420

=26/420

= 13/210

Work done in 16 * 3  = 48 days  

= 16 * 13/210

= 208/210

Work left  = 2/210 = 1/105

1/105 Work done by A  in    (1/105)/(1/84) = 4/5  day

Hence work will be completed in  48 4/5 Days

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