Chemistry, asked by teju0207, 1 year ago


c. CO decays with half-life of 5.27 years to
produce Ni. What is the decay constant
for such radioactive disintegration ?
a. 0.132 ył b. 0.138 c. 29.6 y d. 13.8%​

Answers

Answered by nashantharayil
5

Answer:

b

Explanation:

o.138

Answered by GulabLachman
5

The decay constant  for such radioactive disintegration is:

A) 0.132 y⁻¹

Half life of any radioactive material is the time taken by it to reduce to half of its initial concentration.

Let us represent half life of the material as T'.

We know, half life = 0.693/Decay constant

So, Decay constant = 0.693/Half life

Here, T' = 5.27 years.

Putting them in the above expression, we get:

Decay constant = 0.693/5.27

= 0.13149 y⁻¹

≈ 0.132 y⁻¹

So, option (A) is correct.

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