c. CO decays with half-life of 5.27 years to
produce Ni. What is the decay constant
for such radioactive disintegration ?
a. 0.132 ył b. 0.138 c. 29.6 y d. 13.8%
Answers
Answered by
5
Answer:
b
Explanation:
o.138
Answered by
5
The decay constant for such radioactive disintegration is:
A) 0.132 y⁻¹
Half life of any radioactive material is the time taken by it to reduce to half of its initial concentration.
Let us represent half life of the material as T'.
We know, half life = 0.693/Decay constant
So, Decay constant = 0.693/Half life
Here, T' = 5.27 years.
Putting them in the above expression, we get:
Decay constant = 0.693/5.27
= 0.13149 y⁻¹
≈ 0.132 y⁻¹
So, option (A) is correct.
Similar questions