(C)
(D
Th
20. Which of the following can be the quantum numbers for an orbital?
(A) n = 4,1 = 4, m = 3
(B) n = 2,1 = 3, m = 1
(C) n = 3,1 = 2, m = -1
(D) n = 3,1 - 0, m = -3
(A
(B.
Answers
L=2m,
L=2m,d=3mm,A=
L=2m,d=3mm,A= 4
L=2m,d=3mm,A= 49π
L=2m,d=3mm,A= 49π
L=2m,d=3mm,A= 49π ×10
L=2m,d=3mm,A= 49π ×10 −6
L=2m,d=3mm,A= 49π ×10 −6 m
L=2m,d=3mm,A= 49π ×10 −6 m 2
L=2m,d=3mm,A= 49π ×10 −6 m 2
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL=
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 4
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .
L=2m,d=3mm,A= 49π ×10 −6 m 2 ΔL= 49π ×10 −6 ×10 11 30×2 =8.48×10 −5 m=0.085mm .