(C) Derive S=ut+-ať by the following graph by completing the graph :(02) S=utt at Velocity time
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Explanation:
Set the problem as a quadratic equation:
s=ut+(1/2)at2
ut+(1/2)at2−s=0
at22+ut−s=0
a2t2+ut−s=0
let a = a2 , b = u, and c = -s
t = −b±b2−(4⋅a⋅c)√(2⋅a)
t = −u±u2−(4⋅a2⋅−s)√(2⋅a2)
t = −u±u2+2⋅a⋅s√a
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