Question

c. Derive the expressions for ‘time of flight
and ‘horizontal range of the ball. 3​

Answer 1

Answer:

The average velocity of a projectile between the instant it crosses one third the maximum height. It is projected with u making an angle θ with the vertical.

There will be a pair of points for which vertical velocities at the same height are in opposite direction and therefore their average sum =0

It is the horizontal velocity which is uniform and hence v

av

=u

x

=ucosθ

For a general point:

Displacement in Y-direction:

y=usinθ×t−

2

gt

2

Displacement in X-direction:

x=ucosθ×t

Now in order to calculate average velocity:

Average Velocity =

Totaltime

NetDisplacement

Explanation:

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