Question

c) Determine the location and values of the absolute maximum and absolute
minimum for the given function:
f(x) = (-x + 2)4 where 0 <x<3​

Answer 1

Answer:

f(x)=x

3

Therefore, f

′

(x)=3x

2

Now, f

′

(x)=0⟹x=0

Then, we evaluate the value of f at critical point x=0 and at the end points of the interval [-2,2].

f(0)=0

f(−2)=−8

f(2)=8

Hence, absolute maximum value of f on [-2,2] is 8 occurring at x = 2 and absolute minimum value of f on [-2,2] is -8 occurring at x = -2.