Math, asked by sanjuera1982, 2 months ago


(c) Divide 20 into two parts such that twice the square of the smaller part is 16 less than the square
of the larger part.​

Answers

Answered by syam74459
1

Step-by-step explanation:

given,

2(20-x)square=xsquare+16

2(400-40+xsquare2)=xsquare +16

800-80x+2xsquare-xsquare -16=0

xsquare -80x+784=0

factorise the remaining part you will get the value of x

Similar questions