c equal to 60 degrees then show that b by c square minus A square + a by c square minus b square equal to zero
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Hlw mate !!
(a + b + c) = 0
Square on both sides,
(a + b + c)^2 = 0^2
a^2 + b^2 + c^2 + 2(ab + bc+ ca) = 0
16 + 2(ab + bc + ca) = 0
2(ab + bc + ca) = -16
ab + bc + ca = -16/2
ab + bc + ca = -8
Hope it helpful
(a + b + c) = 0
Square on both sides,
(a + b + c)^2 = 0^2
a^2 + b^2 + c^2 + 2(ab + bc+ ca) = 0
16 + 2(ab + bc + ca) = 0
2(ab + bc + ca) = -16
ab + bc + ca = -16/2
ab + bc + ca = -8
Hope it helpful
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