Question

(c)
Find the altitude and area of an isosceles triangle whose perimeter is 64 cm and
whose base is 24 cm.
​

Answer 1

Answer:

altitude of an isosceles triangle are always perpendicular to the base and divides the base in two equal parts that is in 24/2=12cm

so, length of altitude,

by Pythagoras theorem

64^2=12^2+(altitude)^2

4096=144+x^2

x^2=4096-144

x^2=3952

x=62.86

Answer 2

Answer:

altitude = 16 cm.

area = 192 cm^2

Step-by-step explanation:

Given,

perimeter = 64 cm.

base= 24 cm.

sum of 2 sides = (64 -24) = 40 cm.

Length of each equal side = 20 cm.

Altitude = 16 cm.

Area = (24 x 8) = 192 cm^2