_______________. (c). Find the amount to be paid at the end of 3 years in each case: (a) Principal = 1,200 at 12% p.a. 2 marks (b) Principal = 7,500 at 5% p.a. 2 marks
10 points
Answers
Given :-
- Principal = 1,200 at 12% p.a.
- Principal = 7,500 at 5% p.a
To find :-
- The amount to be paid at the end of 3 years in each of case.
Solution :-
As we know that
→ Simple interest = principal × rate × time/100
→ S.I = P × R × T/100
- In first case
→ Principal = 1,200 at 12% p.a and time 3 years
So,
→ S.I = P × R × T/100
→ S.I = 1200 × 12 × 3/100
→ S.I = 12 × 12 × 3
→ S.I = 144 × 3
→ S.I = Rs.432
Hence,
→ Amount = Principal + S.I
→ A = 1200 + 432
→ A = Rs.1632
- In second case
→ Principal = 7,500 at 5% p.a and time 3 years
So,
→ S.I = P × R × T/100
→ S.I = 7500 × 5 × 3/100
→ S.I = 75 × 5 × 3
→ S.I = 75 × 15
→ S.I = Rs.1125
Hence,
→ Amount = Principal + Simple interest
→ A = 7500 + 1125
→ A = Rs.8625
Therefore,
Amount in first case = Rs.1632
Amount in second case = Rs.8625
a) Given :
- P = ₹ 1200
- R = 12 %
- T = 3 years
To find :
- Amount to be paid
Formula :
✯ S. I = P × R × T / 100
According to the question :
⟹ S. I = 1200 × 12 × 3 / 100
⟹ S.I = 43200 / 100
⟹ S. I = ₹ 432
➳ Amount = P + S. I
⟹ ₹ 1200 + 432
⟹ ₹ 1632
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
b) Given :
- P = ₹ 7500
- R = 5 %
- T = 3 years
To find :
- Amount to be paid
Formula :
✯ S. I = P × R × T / 100
According to the question :
⟹ S. I = ₹ 7500 × 5 × 3 / 100
⟹ S. I = 112500 / 100
⟹ S. I = ₹ 1125
➳ Amount = P + S. I
⟹ ₹ 7500 + 1125
⟹ ₹ 8625
Finally We found :
a) ₹ 1632
b) ₹ 8625