Math, asked by aman2intouch, 4 months ago

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Find the area of a rhombus, the lengths of whose diagonals are 14 cm and 16 cm.​

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Answered by Anonymous
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Answered by Anonymous
11

Given:-

  • Diagonals of a rhombus are 14 cm and 16 cm.

To find:-

  • Area of a rhombus.

Solution:-

Here,

  • D1 = 14 cm
  • D2 = 16 cm

Formula used:-

Area of rhombus = 1/2 × D1 × D2

→ 1/2 × D1 × D2

→ 1/2 × 14 × 16

→ 1/2 × 224

112 cm²

Hence,

  • the area of a rhombus is 112 cm².

More Formulas:-

→ Area of rectangle = length × breadth sq.units

→ Perimeter of square = 4 × side units

→ Area of square = side × side sq.units

→ Perimeter of circle = 2πr units

→ Area of circle = πr² sq.units

→ Perimeter of parallelogram = 2 × (a + b) units

→ Area of parallelogram = base × height sq.units

→ Perimeter of rhombus = 4 × side units

→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units

→ Perimeter of equilateral triangle = 3 × side units

→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units

→ Perimeter of trapezoid = (Sum of all sides) units

→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units

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