(c) Find the co-ordinate of the foot of the
perpendicular from the points (-1, 3) to the line 3x – 4y - 16 = 0.
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let (a,b) be the coordinates
slope of line joining (-1,3)&(a,b) is m1=b-3/a+1
slope of line 3x-4y-16=0 or 3/4x-4, m2=3/4
since these 2 lines are perpendicular,m1m2=-1
{b-3/a+1}.{3/4}=-1
3b-9/4a+4=-1
3b-9=4a-4
4a+3b=5...(1)
point(a,b) lies on line 3x-4y=16
3a-4b=16...(2)
solve 1 &2
a=68/25. b=-49/25
ans=68/25,49/25
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