(c) Find the equation to the straight line which passes through the point P(2,6) and cuts the co-ordinate axes at the points A and B respectimely so that AP/BP = ⅔
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Answer:
Straight line equation point (2,6)
BP
AP
=
3
2
by section formula
p(2,6)=(
5
0+3x
,
5
2y+0
)
p(2,6)=(
5
3x
,
5
2y
)
∴
5
3x
=2 &
5
2y
=6
x=
3
10
y=15
Equation of line
∴
y
2
−y
1
y−y
1
=
x
2
−x
1
x−x
1
∴
15−0
y−0
=
0−
3
10
x−
3
10
∴
15
4
=
−10/3
x−10/3
∴
15
4
×
3
−10
=x−10/3
∴
9
−2y
=
3
3×−10
∴−2y=3(3x+0)
∴−2y=9x−30
∴9x+2y−30=0.
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