Question

(C)
Find the greatest number of 5-digits which when
divided by 3, 5, 8 and 12 will have 2 as remainder​

Answer 1

Answer:

3 - 2 = 1

5 - 2 = 3

8 - 2 = 6

12 - 2 = 10

Taking the LCM of 1,3,6,10 = 30

greatest 5 digit number is 99999

so 99999/30 we are left with remainder 9

99999 - 9 = 99990

So greatest 5 digit number divisible by 30 is 99990

and 99992 is the number when divided by 3,5,8,12 will always leave remainder 2

Step-by-step explanation: