Question

c) Form an equation for the following situation:
Raju's father's age is 5 years more than three times Raju's age. Raju's father is 44
years old.​

Answer 1

Given:

• Raju's father's age is 5 years more than three times Raju's age.
• Raju's father is 44 years old.

Equation formed:

Let Raju's age be 'x' years.

• Raju's father's age is 5 years more than three times Raju's age. = 3x+5

Now, combining both the statements,

3x + 5 = 44 --> This is the equation formed.

Let's solve it!

Solution:

$\implies \sf {3x + 5 = 44}$

$\implies \sf {3x = 44-5}$

$\implies \sf {3x = 39}$

$\implies \sf {x = \dfrac{39}{3}}$

$\boxed {\mathfrak {\red {x=13}}}$

Verification:

Substitute the value of 'x' as 13 in the equation,

$\implies \sf {3x + 5 = 44}$

$\implies \sf {3 \times 13 + 5 = 44}$

$\implies \sf {39 + 5 = 44}$

$\implies \sf {44 = 44}$

LHS = RHS

Hence Verified!

Present ages:

• Raju's present age is 13 years.
• Raju's father's present age is 44 years.
• Equation formed (3x+5 = 44).