c) From the sum of 3a+b + Sb-a - 7ab and
2ab + 12 a b + 5. subtract the sum of
4b-a + 14 and 9ab - 16.
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subtract 4a−7ab+3b+12 from 12a−9ab+5b−3
=12a−9ab+5b−3−(4a−7ab+3b+12)
=12a−9ab+5b−3−4a+7ab−3b−12
=8a−2ab+2b−15
This is ur anwer
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