Question

(C) Given:CD is a chord
of a circle with
centre 0.
OM I CD.
Prove that:CM =DM
O
C С
M
D​

Answer 1

In ∆OCM and ∆ODM

OC=OD ( radius of the circle)

OMC=OMD ( both angles are 90 degree)

OM=OM ( common)

∆OCM congruence to ∆∆ODM

so CM=DM ( corresponding angles of congruent Triangle )