C has half life of 20 min.initial sample has 1000 nuclei How Many nuclei will be left after (a) 40min (b) 60 min.
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Explanation:
t½ = 20 min.
No = 1000
N / No = (1 /2) ^ n
T = n t½
a. T = 40min.
40 = n x 20
n = 2
N / No = ( 1/2) ^ 2 = 1/4
N = No/4 = 1000/4 = 250 nuclei undecay.
b. T = 60 min.
60 = n x 20
n = 3
N/No = (1/2)^ n = (1/2)^ 3 = 1/8
N = No /8. = 1000/8 = 125 nulcei undecay
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