Question

c) how does the gravitational force between two objects change if distance is required to 1\4 that?​

Answer 1

answer :-

g = M1/ d²

force due to gravtional = m2× g

so , f directly proportional to 1/d²

when distance is d/4

=> f' is proportional to 1/ (d/4)²

=> f' is proportional to 16/d²

hence , f' = 16f

therefore , final force change to sixteenth time of intial force .

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