Question

C.I-30000 rate = 9%. ( Time - 3 years.
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Answer 1

Correct Question:-

Rs.30000 at the rate of 9% compound interest per annum 3 years.

Given:-

:⟹Principal(p)=30000rupees

:⟹Rate%(r)=9%

:⟹Time(t)=3years

To Find:

:⟹Compound Interest(C.I)=?

• According to given question :

$\begin{gathered} \bold{we \: know \: that} \\ \tt: \implies A= p(1 + \frac{ {r} }{100} )^{t} \\ \\ \tt: \implies A=30000 \times (1 + \frac{9}{100} )^{ 3} \\ \\ \tt: \implies A =30000 \times (1 + 0.09)^{3} \\ \\ \tt: \implies A=30000 \times {(1.09)}^{3} \\ \\ \tt: \implies A =30000 \times 1.295029 \\ \\ \red{\tt: \implies A=38850.87 \: rupees} \\ \\ \bold{For \: compound \: interest : } \\ \tt: \implies C.I=A - P \\ \\ \tt: \implies C.I =38850.87 - 30000\\ \\ \red{\tt: \implies C.I =8850.87 \: rupees}\end{gathered}$