C.I. f calculate MD AMZ o-5 ,3 5-10, 8, 10-15, 5, 15-20 ,9, 20-25, 1, 25-30, 4
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Answer:
Here N/2 = 33 , which lies in the interval 10-15 .
So , the lower limit of the median class is 10 .
Explanation:
The highest frequency is 20 , which lies in the interval 15-2 .
Therefore , the lower limit of model class is 15 , So they required sum is
10+15=25 .
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