Math, asked by venky356, 1 year ago

C.I. on a sum is 320 in 2nd year & 2000 in 4th year. C.I. in the 3rd year ?​

Answers

Answered by krunker
2

Answer:

Step-by-step explanation:

Answered by amitnrw
0

Answer:

Rs 800

Step-by-step explanation:

Let say Principal = P

Let say interest Rate = 100R %  per annum

Interest in 1st Year = P100R/100 =  Rs PR

Interest in two years = P( 1 + 100R/100)² - P

Interest in second Year = Interest in two years - interest in 1st Year

P( 1 + R)² - P - PR =  320

=> P ( 1 + R² + 2R - 1 - R) = 320

=> P (R² + R) = 320

=> PR(R + 1) = 320   - eq 1

Interest in 4 years  = P( 1 + R)⁴ - P

Interest in 3 years  = P( 1 + R)³ - P

interest in 4th year = P( 1 + R)⁴ - P( 1 + R)³

P( 1 + R)⁴ - P( 1 + R)³ = 2000

=> P( 1 + R)³ ( 1 + R - 1) = 2000

=> P( 1 + R)³ (R) = 2000   eq2

eq 2/ eq1

(1 + R)² = 2000/320

=> ( 1 + R)² = 100/16

=> ( 1 + R)² = 10/4

=> 1 + R = 2.5

=> R = 1.5

interest Rate =  100R = 150 % per annum

P(1.5)(1.5 + 1) = 320

=> P = 256/3

compound interest in 3rd year = P( 1 + R)³ - P( 1 + R)²

= PR(1 + R)²

=PR(1+R)(1+R)

= 320(1 + R)

= 320(1 + 1.5)

= 320(2.5)

= 800

Amount         Rate     Interest

85.33333333 150% 128

213.3333333 150% 320

533.3333333 150% 800

1333.333333 150% 2000

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