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A uniform wire of resistance 5012 is cut into five equal parts. These parts are now connected in
parallel
. Then the equivalent resistance of the combination
A-2
B-12
C-250
D-6250
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Answer:
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Explanation:
ANSWER
We know that R∝l
On cutting the wire into five equal parts, length of each part becomes one-fifth and hence resistance of each part=R=
5
50
=10Ω
When all five wires of resistance R are connected in parallel, equivalent resistance becomes
5
R
=
5
10
=2Ω
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