(c) If 10 m long manganin wire, 0.13 cm in diameter has resistance of
3.4 Ω , find the resistivity (rho) of the manganin wire. [2
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Explanation:
here, it is Given that:
I=1m,d=0.2mm->r=0.1mm and R=10 ohm
by using the formula,
R= pl/ A
=pl/πr²
therefore, p= Rπr²/1
= 10× 3.14×( 0.1× 10 -³)²
= 10× 3.14× 0.1×0.1× 10 to the power -6
= 0.314x 10 to the power-6
= 3.14x 10 to the power-7 ohm- m
hence, the resistivity of the conductor is 3.14× 10 to the power-7 ohm- m
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