Question

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If 2 and - 2 are zeroes of p(x).
find the values of a and b.

$p(x) = {ax}^{4} + {2x}^{3 } - {3x}^{2} + bx - 4$
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Answer 1

Step-by-step explanation:

2 and -2 are the zeroes

(x+2)(x-2)=0

x^2-4=0

x^2=4

x=2---------------(1)

substitute equation 1in the quadratic equation

p(x)=(a*2)^4+(2*2)^3-(3*2)^2+b*4=0

16a^4+64-36+4b=0

16a^4+28+4b=0

16a^4+4b=-28