Question

(c) If sin 3A = cos (A-26°), where 3A is an acute angle, find the value of A​

Answer 1

Answer:

A=29o

Step-by-step explanation:

Given that

sin3A=cos(A−26)

cos(90−3A)=cos(A−26)             [sinθ=cos(90−θ)]

Comparing angles

90−3A=A−26

−3A−A=−26−90

−4A=−116

A=4116

A=29o

I hope you understand..

Answer 2

Answer:

sin 3A = cos (A-26°)

cos(90°-3A)=cos (A-26°)

90°-3A=A-26°

90°+26°=A+3A

116°=4A

A=29°