Question

© In AABC, AB - 3cm, BC = 2cm, AL = 2.5cm, ADH
AA BC, EF:4cmThe perimetes of ADEF

Answer 1

Answer:

AD = 1.5 cm

Step-by-step explanation:

Consider ΔABC and DE║BC,  AB = 6cm, let AC = x the AE = \frac{x}{4}4x

Consider ΔABC and ΔADE

∠ABC= ∠ADC (corresponding angles are equal as  DE║BC)

∠BAC = ∠DAC (common angle)

Since, two angles are similar, therefore by properties of similarity of triangle,

ΔABC\sim∼ ΔADC

Also, if triangles are similar, their sides are in proportion,

∴ \frac{AD}{AB} = \frac{AE}{EC}ABAD=ECAE

\frac{AD}{6} = \frac{$\frac{x}{4} }{x}$

\frac{AD}{6} = [tex]\frac{1}{4}6AD=[tex]41

AD = 1.5 cm