(c) In square ABCD, AD = 8b-9; AB =9-b, Find CD
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Step-by-step explanation:
simple calculation using pythagoras theorem ,
AD^2 = AB^2+ CD^2
64b^2 + 81 - 144b = 81+ b^2 + -18b +CD^2
....CD = (63b^2 + 124b)^1/2
now solve as it is ....
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