Question

(c) In the adjoining figure, all measurements are in centimeters. Find (i) AC (ii) CE Hence prove that AE2 = AC2 + CE2. Also state the measure of angle ACE​

Answer 1

Answer:

[tex]In △ADC

AD2+DC2=AC2

DC2=252−52=625−25

=600

DC=600=24.495

BD=BC−DC

=28−24.495

=3.505

In △ADB∠ADB=90

AB2=AD2+BD2

=52+(3.505)2

AB2=37.285

AB=6.1cm

Answer 2

Answer:

$In △ADC</p><p></p><p></p><p>AD2+DC2=AC2</p><p></p><p></p><p>DC2=252−52=625−25</p><p></p><p></p><p>=600</p><p></p><p></p><p>DC=600=24.495</p><p></p><p></p><p>BD=BC−DC</p><p></p><p></p><p>=28−24.495</p><p></p><p></p><p>=3.505</p><p></p><p></p><p>In △ADB∠ADB=90</p><p></p><p></p><p>AB2=AD2+BD2</p><p></p><p></p><p>=52+(3.505)2</p><p></p><p></p><p>AB2=37.285</p><p></p><p></p><p>AB=6.1cm</p><p></p><p>$