Question

(c)
in the given diagram 'O' is the centre of the circle and AB is parallel to CD.
AB = 24 cm and distance between the chords AB and CD is 17 cm. If the radius
of the circle is 13 cm, find the length of the chord CD.​

Answer 1

Step-by-step explanation:

1st see the diagram

Now,

AB = 24 cm EB = 12 cm (by theorem)

Draw OB and OB is given 13 cm

For EOB,

OB = 13 cm EB = 12 cm

therefore,

OE = √(13²−12²)

= √(169-144)

= √25

= 5

so, OB = 5 cm

Now, EF = 17 cm OF = EF-OB = 12 cm

Draw OD

ForOFD,

OF = 12 cm OD = 13 cm

therefore,

FD = √(13²-12²)

= √(169-144)

= √25

= 5

so, FD = 5 cm

Now,

2FD = CD (by theorem)

so, CD = 10 cm

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