Question

(c) In the given figure, D is mid-point of AB, DE||BC and DF |AC. Prove that DE=BF​

Answer 1

Step-by-step explanation:

In triangle ABC

D is the midpoint of BC

DE perpendicular to AB

And DF perpendicular to AC

DE=DF

To prove:

Triangle ABC is an isosceles triangle

Proof:

In the right angles triangle BED and CDF

Hypotenuse BD=DC ( because D is a midpoint )

Side DF=DE ( given)

△BED≅CDF ( RHS axiom)

∠C=∠B

AB=AC ( sides opposite to equal angles

△ABC is an isosceles triangle

Answer 2

Answer:

import java.util.Scanner;

public class KboatMegaShop

{

public static void main(String args[]) {

Scanner in = new Scanner(System.in);

System.out.println("1. Ground floor");

System.out.println("2. First floor");

System.out.println("3. Second floor");

System.out.println("4. Third floor");

System.out.print("Select a floor: ");

int floor = in.nextInt();

boolean isFloorValid = true;

switch (floor) {

case 1:

System.out.println("Kids Wear");

break;

case 2:

System.out.println("Ladies Wear");

break;

case 3:

System.out.println("Designer Sarees");

break;

case 4:

System.out.println("Men's Wear");

break;

default:

isFloorValid = false;

System.out.println("Incorrect Floor");

break;

}

if (isFloorValid) {

System.out.print("Enter bill amount: ");

double amt = in.nextDouble();

System.out.println("Name of the Shop: City Mart");

System.out.println("Total Amount: " + amt);

System.out.println("Visit Again!!");

}

}

}