Question

c) in the reaction represented by the equation:

MnO2 + 4HCl MnCl2 + 2H2O + Cl2

a. Name the substance oxidized
b) name the oxidizing agent
c. Name the substance reduced
d) name the reducing agent

Answer 1

Answer:

MnO₂ + 4HCl ---> MnCl₂ + 2H₂O + Cl₂

a) Here Chlorine converts from -1 to 0 oxidation state, so the substance oxidised is HCl

b) MnO₂ is reducing itself while oxidising HCl, so oxidising agent is MnO₂

c) Mn is reduced from +4 to +2 oxidation state, so the substance reduced is MnO₂

d) HCl is oxidising itself while reducing MnO₂ , so reducing agent is HCl

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