c. In what time 600 dyne force acting on 1 kg mass at rest,
produces the velocity of 3 m s'?
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Answer:
Step-by-step explanation:
force= mass x acceleration
acceleration=velocity/time
1 newton= 10^5 dynes
1 dyne = 10^-5 Newton
600 dynes=600 x 10^-5 N
So, F = 6 x 10^-3 N
m= 1 kg a = F/m = 6 x 10^-3/1 = 6 x 10^-3 m/s^2
a=v-u/t here, u = 0
a= v/t
t=v/a
= 3/6 x 10^-3 = 5 X 10^-4 s
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