Question

C is a s circle with centre (0,0)
L is a straight line with negative gradient.
The circle C and the line L intersect at the points A and B.

The coordinates of A are (-9,2) The x coordinate of Bis 7

Find an equation of L.​

Answer 1

Answer:

the equation of circle will be x^2+y^2=a^2

1.put the value of point A and find value of a.

2.find B coordinate.

Step-by-step explanation:

1.

81+4=a^2

2.

49+y^2=85

y^2=36

y=+-6

so we got point A(-9,2) and point B(7,6) and B(7,-6)

so there could be two equition of line L.

you got the two points and now you can find the slope and put the value of slop into standard equation of line.