Question

c is the centre of the circle seg Qt is a diamerer ct is 13 cp is 5 find the length of the chord Rs

Answer 1

Solution:-

given by:- C is the centre of the circle.
CT = 13
CP = 5 
THEN , 
QP = CT - CP = 13-5 = 8
in Triangle SPC
HERE , CS = 13 , CP = 5 
(cs)^2 = (ps)^2 + (cp)^2
(ps)^2 = (cs)^2 - (cp)^2
(ps)^2 = 13^2 - 5^2
(ps)^2 = 169 - 25
ps^2 = 144
ps = √144
ps= 12
PS = 12 , 
THEN
RS = 2×PS 

CHORD RS = 2×12 = 24