Math, asked by fkelamami, 11 months ago

C is the circle with equation x^2+y^2=1
Q (1/2, √3/2) is a point on C
The equation of the tangent to C at the point Q can be written in the form y=ax+b
Find the value of a and the value of b.

Answers

Answered by ksangameshwar14
3
  • Answer:

given circle s=x^2+y^2-1=0,

  • tangent at point Q (1/2,root3/2) the equation of tangent to the circle s1=0 find eqn at point Q or different eqn of circle at point Q and compare with eqn y= ax+b
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