C is twice efficient as a and b is thrice time consume than
c.of a complete alone work in 12 days then find how many days all complete the work.
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C is twice efficient as A
efficiency is inversely proportional to time
A takes 12 days to complete so C will take 6 days
And B takes thrice the time of C
So B takes 18 days
Now total work = LCM of 12, 6, 18 = 36
1 day work = 1/12 + 1/6 + 1/18 = (3+6+2) / 36 = 11/36
so whole work will be completed in 36/11 days = 3 3/11 days
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