Question

C केंद्र असलेल्या वर्तुळाच्या कंस ADB मध्ये ∠ADB अंतर्लिखित केलेला आहे. जर m∠ADB = 65°, तर m(कंस ADB) व m(कंस AB) काढा. *
2 points​

Answer 1

Solution :-

given that,

→ ∠ADB = 65°

→ C = centre of circle .

So,

→ ∠ADB = (1/2)•m(arc AB) { The measure of an inscribed angle is half of the measure of the arc intercepted by it . }

→ m(arc AB) = 2•∠ADB

→ m(arc AB) = 2 * 65°

→ m(arc AB) = 130°

then,

→ m(arc ADB) = 360° - m(arc AB)

→ m(arc ADB) = 360° - 130°

→ m(arc ADB) = 230°

therefore, m(arc ADB) is equal to 230° and m(arc AB) is equal to 130° .

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