Math, asked by vaishnavisinha90, 11 months ago

(c) Lead dioxide + Hydrochloric acid → Lead chloride + Water + Chlorine
(d) Aluminium oxide + Sulphuric acid → Aluminium sulphate + Water
(e) Iron + Conc. Sulphuric acid → Iron (II) Sulphate + Sulphur dioxide gas + Water,
write the formula ​

Answers

Answered by raghavkashyap1972
12

Answer:

Step-by-step explanation:

1) Lead dioxide + Hydrochloric acid → Lead chloride + Water + Chlorine

⇒ PbO2 + HCl = PbCl2 + Cl2 + H2O

2)  Aluminium oxide + Sulphuric acid → Aluminium sulphate + Water

⇒ Al2O3 + H2SO4 = Al2(SO4)3 + H2O

3)  Iron + Conc. Sulphuric acid → Iron (II) Sulphate + Sulphur dioxide gas + Water

⇒ Fe + H2SO4 = Fe2(SO4)3 + SO2 + H2O

Hope This Helps!

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