(c) Mr X was five times as old as Mr Y before five years. Mr X will be three times as old as Mr Y after
three years. Find their current ages.
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Step-by-step explanation:
Let the father present age =x years and son present age =y years
According to the first condition
5 years later father will be (x+5) years old and son will be (y+5) years old.
⇒x+5=3(y+5)
⇒x+5=3y+15⇒x=3y+10....eq1
According to the second condition
5 years ago father was (x−5) years old and son was (y−5) years old.
⇒x−5=7(y−5)
⇒x−5=7y−35
⇒x−7y=−30....eq2
Put the value of x from eq1
⇒3y+10−7y=−30⇒−4y=−40⇒y=10
Put y=10 in eq1
⇒x=3×10+10=40
Hence, Father present age =40 years
Son present age =10 years
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