C(n,10) = C(n,14) then C(25,n) is ?
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n
C
10
=
n
C
15
. ....(1)
We know that
n
C
r
=
n
C
n−r
,
n
C
10
=
n
C
n−10
=
n
C
15
, ....by (1)
∴ n - 10 =15 or n = 25
or If
n
C
x
=
n
C
y
then x + y = n.
Hence from (1), we get 10 + 15 = 25= n
∴
27
C
n
=
27
C
25
=
27
C
27−25
=
27
C
2
=
1×2
27×26
=27×13=351
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