Question

c) Non uniform acceleration
dy No need to consider acceleration
Two bodies ‘A’and 'B' are connected by a string over a pulley (see the fig). The distance covered by
‘A’ is same as the distance covered by 'B', but their directions are different. Then [ ]
a) A can't be treated as a system
A
b) (A + B) can't be treated as a system
c) B can't be treated as a system
B
d) A can't be treated as a system but B can be treated as a system.


what is the option


please tell me as soon as possible​

Answer 1

Explanation:

Force balance equations for two weights can be written as:

T

1

=m

1

g−m

1

a---------(i)

and T

2

=m

2

a+m

2

g----------(ii)

(ii)-(i), we get:

T

1

−T

2

=(m

1

−m

2

)g−(m

1

+m

2

)a------------(iii)

As torque, τ=Iα, we have:

(T

1

−T

2

)R=(

2

1

MR

2

).

R

a

or, T

1

−T

2

=

2

Ma

Substituting this in equation (iii), we get:

2

Ma

=(m

1

−m

2

)g−(m

1

+m

2

)a

or, a=

m

1

+m

2

+(m/2)

(m

1

−m

2

)g