Question

C. Numericals :
1. Find the moment of force of 20 N about an axis
of rotation at a distance of 0.5 m from the force.
Ans. 10 Nm​

Answer 1

Answer:

10N

Explanation:

10N

10

10

1

.1

.01

.00q

Answer 2

Answer:

Moment of force = Force \times perpendicular distance of force from point of rotation

= F\times \bot distance

= 20N 0.5m

= 10Nm

Explanation:

hope you understand