C)
ou degree
d) 90 degree
Q(27) If the linear momentum is increased by 50%, then kinetic energy is increased by
a) 50%
b) 100%
c) 125%
d) 25%
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If the initial momentum is p 0
, the initial kinetic energy is K o = Po ( square )
2m
2m
2m
2m
2m When momentum is increased by 50 %, the
momentum becomes p = p o
100 = [(9/4) − 1] 100= 125 %
Hope it's helpful
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