Question

C paUu. The length and breadth of Mihir's rectangular garden is 50m. and 30m. respectively. There 1s a road in the middle of the garden of width 4m. parallel to the length of the garden. This road divides the garden into two rectangular regions of equal area. Let's draw a picture and find out the area of the road and note it down.

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Answer 1

Length of the rectangular lawn=75m

Breadth of the lawn=60m

Width of the road=4m

Area of the road(ABCD) parallel to the length of the lawn = 75m×4m

                                                                               =300m2

Area of the road(EFGH) parallel to the breadth of the lawn = 60m×4m

                                                                               =240m2

Area of the common area in both ABCD and EFGH = 4m×4m

                                                                               =16m2

Total area of both the rectangular roads = 300+240−16

                                                                     =524m2

Cost of gravelling the roads per m2= Rs.4.50

Cost of gravelling the roads for 524m2

                                                      =4.50×524

                                                      =2358

Cost of gravelling the road is Rs.2358

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PLS MARK AND BRAINLIST